facebook tracking Plastic surgeons in Pomona, NY (1 doctor)

Plastic surgeons in Pomona, NY

1 Medicare-enrolled plastic surgeon practices in Pomona. The hospital they most often list is Nyack Hospital. Filter by Medicare acceptance, telehealth or hospital below.

Plastic surgeons1practicing in Pomona
Accept Medicare100%1 of 1
Offer telehealth0%0 plastic surgeons
Typical experience48 yrs0 women, 1 men

Hospitals they work with

Every plastic surgeon in Pomona

Lawrence S. Glassman, MD

Plastic And Reconstructive Surgery48 years in practice

978 Route 45, Suite L5, Pomona, NY 10970

(845) 354-7878
Accepts Medicare assignment Johns Hopkins University School Of Medicine

Hospital affiliations

NPI 1477692440

No plastic surgeon here matches those filters.

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Other doctors in Pomona

Plastic surgeons elsewhere in New York

Questions about plastic surgeons in Pomona

How many plastic surgeons are in Pomona, NY?

1 Medicare-enrolled plastic surgeon practices in Pomona according to CMS.

Which hospitals do Pomona plastic surgeons work with?

The hospitals Pomona plastic surgeons most often list as an affiliation are Nyack Hospital (1). An affiliation usually means the doctor can treat or admit patients there.

Do these plastic surgeons accept Medicare?

All are enrolled in Medicare. 1 of 1 accept Medicare assignment, meaning they take the Medicare-approved amount as full payment for covered services. 0 offer telehealth visits. Confirm with the office before booking, especially if you have Medicare Advantage or private insurance.

What does a plastic surgeon do?

Plastic surgeons perform reconstructive surgery after injury, cancer or birth defects, and cosmetic procedures.

Listings come from the CMS Doctors and Clinicians national file: clinicians enrolled in Medicare whose primary specialty is plastic and reconstructive surgery, at the practice addresses CMS lists in Pomona. Hospital affiliations are the hospitals each clinician reports to Medicare. Details change; confirm with the practice before you visit. About the data.